Error analysis, multiplying an error

AI Thread Summary
When multiplying a value with an associated error, such as ΔT with a mass (m), the error in the resulting product (y) is proportional to the constant factor (m). If ΔT has an error of one degree, the error in y will also reflect that, remaining consistent across different values of m. The relationship can be understood through the concept of derivatives, where the error in y is determined by the derivative of the function multiplied by the error in x. Thus, for a linear relationship, the error in y remains a constant multiple of the error in x. This understanding is essential for accurately plotting values on a graph.
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Equation: M (ΔT)=
The question:
If ΔT has an error of one degree, and i multiply it by the mass of an object (m) is the error in y still one

Attempted answer: or is it proportional to M i.e Δt plus or minus 1 degrees so the error in y is 2M?


P.S i need to be able to know the error for a whole bunch of values because I am putting m delta t as an axis on a graph, would i have to work it out for each value of m ΔT
 
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Hi welcome to physicsforums. :smile:

I suppose that with "degree", you mean degree Celcius. If you multiply with a constant (thus the constant has no or negligible error) then the percentual error remains the same.

You can find that answer yourself simply by trying:

5x20=100
5x21=105
 
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generally speaking, if you have an error in x then the error in y will be the derivative of the function used on x times the error in x. for a straight line, the derivative is a constant value, thus the error in y is a constant value times the error in x.
 
yeah thanks harrylin that's exactly what i was trying to figure out, much appreciated
 
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