Error propagation when dividing by exact number

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SUMMARY

The discussion focuses on error propagation in the calculation of moles of acetylsalicylic acid using spectrophotometry. The measured mass is 0.1620 ± 0.0005g, and the molar mass is 180.2 g/mol. The participant correctly identifies that the error from the spectrophotometric measurement (±0.0005) is significant enough to disregard the weight error range of 0.03%. The final calculated moles are presented as 8.990 ± 0.0277 × 10-4 mol.

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  • Understanding of basic chemistry concepts, specifically molar mass and moles.
  • Familiarity with error propagation techniques in measurements.
  • Knowledge of spectrophotometry and its associated error margins.
  • Experience with significant figures and their application in scientific calculations.
NEXT STEPS
  • Research "Error propagation in chemistry" for detailed methodologies.
  • Learn about "Significant figures in scientific calculations" to enhance accuracy.
  • Explore "Spectrophotometric measurement techniques" for improved understanding.
  • Study "Calculating moles and molar mass" to solidify foundational knowledge.
USEFUL FOR

Chemistry students, laboratory technicians, and anyone involved in quantitative analysis using spectrophotometry will benefit from this discussion.

NihalRi
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Homework Statement


Some Background - We are calculating the amount of acetylsalicylic acid in a sample using spectrophotometry. We were told to make sure to include the error in our answer. So first to calculate the moles of acetylsalicylic acid in a measured mass.

0.1620 ± 0.0005g measured using a digital balance
180.2gmol-1 (molar mass of acetylsalicylic acid given in book)

2. Homework Equations

Mass/molar mass = moles

3. The Attempt at a Solution

0.1620 ± 0.0005g/180.2gmol-1
I know that we divide the number and error by the fixed value but the error has way too many numbers so I am not sure how much to keep. My first guess is one more decimal place than the value but this does not make sense to me because is seems like there are too many significant digits in the answer for such a large error.

8.990±0.0277×10-4mol

Calculating errors has always been a nightmare for me especially when the numbers are not pretty, I'd like to get this thing down so I would greatly appreciate your help.
 
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My reaction is to think you need to know what the error of your spectrophotometric measurement is . and my guess is that this is so sufficiently more than the 0.03% is that right? weight error range that you don't need to bother about latter .
 
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epenguin said:
My reaction is to think you need to know what the error of your spectrophotometric measurement is . and my guess is that this is so sufficiently more than the 0.03% is that right? weight error range that you don't need to bother about latter .

Yes, I can get the error from the spectrophotometric measurement which is ±0.0005 from the readings which is around 0.09% for my first reading and 0.48% for my last. So I don't need to bother with calculating the error in the concentration. Got it thanks :)
 

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