Establish a [itex]\bullet[/itex] 0 = 0

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Homework Help Overview

The discussion revolves around establishing the equation \( a \bullet 0 = 0 \) within the context of a field, where \( \bullet \) represents multiplication. Participants are exploring the properties of fields and the implications of axioms related to multiplication and addition.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants are attempting to use axioms related to fields to justify the equation. Questions are raised about the definitions of the elements involved, such as the nature of \( a \) and the operation \( \bullet \). There is a focus on the properties of zero and the identities in a field.

Discussion Status

The discussion is active, with various participants providing insights and approaches. Some have suggested using axioms to support their reasoning, while others are questioning the clarity of the initial problem statement and the assumptions made. There is no explicit consensus yet, but several productive lines of reasoning are being explored.

Contextual Notes

Participants note the importance of understanding the definitions and properties of elements in a field, including the existence of additive and multiplicative identities. There is an emphasis on the axioms that govern operations within the field.

smerhej
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Homework Statement



Establish a [itex]\bullet[/itex] 0 = 0

Homework Equations



A few axioms I thought to be relevant..

The Attempt at a Solution



a = a

a [itex]\bullet[/itex] 0 = 0 [itex]\bullet[/itex] a

(a [itex]\bullet[/itex] 0) - (0 [itex]\bullet[/itex] a) = 0

a(1 [itex]\bullet[/itex] 0) - a(0 [itex]\bullet[/itex] 1) = 0

a[(1 [itex]\bullet[/itex] 0) - (0 [itex]\bullet[/itex] 1)] = 0

a [itex]\bullet[/itex] 0 = 0
 
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smerhej said:

Homework Statement



Establish a [itex]\bullet[/itex] 0 = 0

Homework Equations



A few axioms I thought to be relevant..

The Attempt at a Solution



a = a

a [itex]\bullet[/itex] 0 = 0 [itex]\bullet[/itex] a

(a [itex]\bullet[/itex] 0) - (0 [itex]\bullet[/itex] a) = 0

a(1 [itex]\bullet[/itex] 0) - a(0 [itex]\bullet[/itex] 1) = 0

a[(1 [itex]\bullet[/itex] 0) - (0 [itex]\bullet[/itex] 1)] = 0

a [itex]\bullet[/itex] 0 = 0

What set does a belong to? What operation does ##\bullet ## represent?

What is the actual problem statement?
 
What we know is a is an element of some field F, and the dot is multiplication. What I wrote as the problem is the entire question.
 
Last edited:
smerhej said:
What we know is a is an element of some field F, and the dot is multiplication. What I wrote as the problem is the entire question.

"element of some field F" wasn't in the original post.

Every element in a field has an additive identity, and every nonzero element has a multiplicative identity.
 
So you want to prove :

a0 = 0 in some field F.

So I'm presuming you're allowed to assume the existence of a unique zero element and unique additive inverses.

Then :

a0 = 0 + a0
= (-(a0) + a0) + a0
...

As much as id like to help you more, the rest should be obvious. Just use the axioms to justify your steps.
 
A similar approach is to use that 0=0+0.

smerhej said:
a = a

a [itex]\bullet[/itex] 0 = 0 [itex]\bullet[/itex] a
In this attempt, you haven't made it clear how the first equality implies the second.
 
[itex]\bullet[/itex] is a label for the operation of multiplication in a field F. There is an operation of addition in the field, for which the following is true:
[tex] x = x + 0, \forall x \in F[/tex]
Multiply by a, and use the distributive law:
[tex] a \bullet x = a \bullet (x + 0)[/tex]
[tex] a \bullet x = a \bullet x + a \bullet 0[/tex]
Use the group properties of addition of the field. What can you say about [itex]a \bullet 0[/itex] then? Similarly, you can multiply from the left and draw a conclusion for [itex]0 \bullet a[/itex].
 

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