Estimate Melting Point of Lead at 100 atm

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The melting point of lead at atmospheric pressure is 327.0 degrees C, with a density decrease from 1.101 x 10^4 to 1.065 x 10^4 kg/m^3 and a latent heat of 24.5 kJ/kg. To estimate the melting point at 100 atm, the Clausius-Clapeyron equation is suggested as a potential method. The user has calculated the energy expended per cubic meter at 1 atm to be 8820 kJ/m^3 but is unsure how to proceed. The discussion highlights a request for assistance in applying the correct principles to solve the problem. Engaging with knowledgeable members is encouraged to clarify the solution process.
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Homework Statement



When lead is melted at atmospheric pressure the melting point is 327.0 degrees C, the density decreases from 1.101 x 10^4 to 1.065 x 10^4 kg/m^3 and the latent heat is 24.5 kJ/kg. Estimate the melting point of lead at a pressure of 100 atm.

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The Attempt at a Solution



Ok so I am not sure what formula/principle I am meant to use to work this out.

I've worked out the energy expended per m^3 at 1atm to be 8820 kJ/m^3... what do i do now :S Thanks
 
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anyone able to help please?
 
Im guessing the clausius-clapeyron equation comes into it but am confused :S surely someone knows how to solve such problems>?
 
Anyoneeeee? surely there must be some Physics PhDs on here?
 
Thanks ehild - you always seem to help with my physics problems!
 
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