Estimate Sun's Rotation Period as a Neutron Star

Click For Summary
SUMMARY

The discussion focuses on estimating the new rotation period of the Sun if it collapses into a neutron star. The Sun's initial radius is 6.96E8 m with a rotation period of 25.3 days. By applying the conservation of angular momentum, the new angular velocity can be calculated using the formula ω_f = (r_i² * ω_i) / (r_f²), where r_f is the neutron star's radius of 5.5 km. The final period T_new is derived from T_new = 2π / ω_f, leading to the conclusion that a conversion error may have affected initial calculations.

PREREQUISITES
  • Understanding of angular momentum conservation
  • Familiarity with rotational dynamics
  • Knowledge of basic physics formulas for angular velocity and period
  • Ability to perform unit conversions (e.g., days to seconds)
NEXT STEPS
  • Study the principles of angular momentum in astrophysics
  • Learn about the properties and characteristics of neutron stars
  • Explore detailed calculations involving moments of inertia
  • Review unit conversion techniques, particularly for time measurements
USEFUL FOR

Students and professionals in astrophysics, physics educators, and anyone interested in the dynamics of stellar evolution and neutron star characteristics.

wildrjetta
Messages
8
Reaction score
0
Could someone help me start this problem. My mind it in the angular momentum mode and I am having trouble seeing where to start on this one. :confused:

The sun's radius is 6.96E8m and it rotates with a period of 25.3d. Estimate the new period of rotation of the sun if it collapses with no loss of mass to become a neutron star of radius 5.5km. Give the result in seconds.

Thank you very much!
 
Physics news on Phys.org
With the given radius you can find I_{initial} and I_{final}. With the given period, find out \omega_{initial}. Then you use conservation of angular momentum to achieve your answer.
 
as such...(you don't need the moments of inertia exactly because it maintains a spherical shape and same mass so those factor out)

(r_i)^2 \omega_i = (r_f)^2 \omega_f
\omega_f = \frac{(r_i)^2 \omega_i}{(r_f)^2}
T_{new} = \frac{2 \pi}{\omega_f}

follow complete done
 
I calculated two different answers, both of which were to my dismay incorrect...but I am thinking that a conversion error might be the culprit. I am having trouble understanding what "a period of 25.3d" is -- as in, what does "d" stand for...should it be a time unit?
 
in a period d=days
 
THANK YOU THANK YOU THANK YOU! to everyone involved in helping with this problem! :biggrin:
 

Similar threads

  • · Replies 7 ·
Replies
7
Views
2K
Replies
1
Views
1K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 1 ·
Replies
1
Views
6K
  • · Replies 6 ·
Replies
6
Views
2K
  • · Replies 2 ·
Replies
2
Views
9K
  • · Replies 0 ·
Replies
0
Views
3K
Replies
19
Views
4K
  • · Replies 9 ·
Replies
9
Views
2K