MHB Evaluate Piecewise-Defined Function....2

  • Thread starter Thread starter mathdad
  • Start date Start date
AI Thread Summary
The discussion evaluates a piecewise-defined function with three segments: y = |x| for -4 ≤ x < 0, y = x^2 for 0 ≤ x < 1, and y = 1/x for 1 ≤ x ≤ 4. For x = 3, the value is calculated as y = 1/3 using the bottom piece. For x = -4, the upper piece gives y = 4. When x = 1/2, the middle piece results in y = 1/4. The evaluation confirms the correctness of these calculations, highlighting the challenges of precalculus.
mathdad
Messages
1,280
Reaction score
0
The following function is a piecewise-defined function.

y = | x | if -4 ≤ x < 0...upper piece

y = x^2 if 0 ≤ x < 1...middle piece

y = 1/x if 1 ≤ x ≤ 4...bottom piece

Evaluate when x = 3, x = -4 and x = 1/2.

For x = 3, use bottom piece.

y = 1/3

For x = -4, use upper piece.

y = | -4 |

y = 4

For x = 1/2, use middle piece

y = (1/2)^2

y = 1/4

Correct?
 
Mathematics news on Phys.org
Yes, correct.
 
Great. Another pad on the back for me. It feels good to get the right answer. Believe it or not, not too many people can handle precalculus. Some people add 1/2 + 3/4 and call themselves a mathematician. If they only knew that math extends beyond elementary school fractions, I think the title of mathematician would go into the toilet.
 
Seemingly by some mathematical coincidence, a hexagon of sides 2,2,7,7, 11, and 11 can be inscribed in a circle of radius 7. The other day I saw a math problem on line, which they said came from a Polish Olympiad, where you compute the length x of the 3rd side which is the same as the radius, so that the sides of length 2,x, and 11 are inscribed on the arc of a semi-circle. The law of cosines applied twice gives the answer for x of exactly 7, but the arithmetic is so complex that the...

Similar threads

Back
Top