Evaluate the triple integral for specified function

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Homework Help Overview

The discussion revolves around evaluating a triple integral for the function f(x,y,z) = x e^(y-2z) over a specified region. The bounds for x are clearly defined, while the bounds for y and z are less straightforward, leading to confusion among participants regarding their setup.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants express uncertainty about how to set up the integral due to the bounds for y and z being less clearly defined. Some suggest that y and z could extend to infinity, proposing limits of (0, ∞) for y and (1, ∞) for z. Others question the implications of the problem's notation and whether the region can be visualized as a rectangular prism.

Discussion Status

There are multiple interpretations of the bounds being discussed, with some participants offering guidance on how to express inequalities correctly. A few have attempted to clarify the region of integration, while others share their experiences with similar problems, noting discrepancies in textbook notation.

Contextual Notes

Participants mention the potential for implied bounds for y and z, and there is a discussion about the notation used in the problem statement, which may affect understanding. Some express concern about the clarity of the problem setup and its implications for integration.

musicmar
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Homework Statement


Evaluate the triple integral for specified function and box B.

f(x,y,z) = x ey-2z
0<x<2, 0<y, z>1
(The < and >'s should be less than or equal to but, I don't know how to write that here)


Homework Equations





The Attempt at a Solution



I know how to evaluate iterated integrals, but I am confused by the bounds in this problem. y and z only have one bound, so I don't know how to set up the integral.
 
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musicmar said:
y and z only have one bound, so I don't know how to set up the integral.


Why don't they just go to infinity then? Why not just take a stab at it and say, let's integrate dzdydx and try anyway to set up reasonable limits? If z>1 then it's limits should be (1,infty}, same dif with y, (0,infty), and x goes from 0 to 2. Here goes:

[tex]\int_0^2 \int_0^{\infty}\int_1^{\infty} xe^{y-2z} dzdydx[/tex]

Now, I haven't tried to integrate that. Maybe when we do, we'll get into a tough integrand to handle. Then may want to consider a different integration order if that would make the integration easier.
 
musicmar said:

Homework Statement


Evaluate the triple integral for specified function and box B.

f(x,y,z) = x ey-2z
0<x<2, 0<y, z>1
(The < and >'s should be less than or equal to but, I don't know how to write that here)
Use <= for less than or equal to, and >= for greater than or equal to.
musicmar said:

Homework Equations





The Attempt at a Solution



I know how to evaluate iterated integrals, but I am confused by the bounds in this problem. y and z only have one bound, so I don't know how to set up the integral.
There are implied bound for y and z.

0 <= y < infinity
1 <= z < infinity

Do you know what the region in this problem looks like?
 
Thank you. Is it a rectangular prism? y >= 0 is a plane bounded by x, and z would provide the height. But does this help me integrate it?
 
I had to work the same problem. I have found discrepancies in the book before regarding notation, so when I couldn't solve the problem I assumed the boundary meant 0≤X≤2; 0≤y,z≤1→0≤y≤1; 0≤z≤1. Alternately, the box B=[0,2], [0,1], [0,1]. When I worked the problem with these boundaries I got the same answer as the book.
Hope it helps.
Also, you can get "less than or equal to" by underlining the "less than" symbol.
 
musicmar said:

Homework Statement


Evaluate the triple integral for specified function and box B.

f(x,y,z) = x ey-2z
0<x<2, 0<y, z>1
(The < and >'s should be less than or equal to but, I don't know how to write that here)


Homework Equations





The Attempt at a Solution



I know how to evaluate iterated integrals, but I am confused by the bounds in this problem. y and z only have one bound, so I don't know how to set up the integral.

You can write <= and >=, or else you can click on the "Quick symbols" from the panel at the side of the input window, to get ≤ and ≥.

RGV
 

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