Evaluating definite integral by substitution

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The discussion focuses on evaluating the integral ∫^∞_1 (t^5/(1+t^3)^3) dt using the substitution u=1/t. Participants express confusion about changing the limits of integration from (∞,1) to (1,0) and how to correctly apply the substitution. There is acknowledgment that the integral can be transformed, but concerns about the sign and limits arise. Clarification is provided that reversing the limits results in a negative sign, which is a standard property of definite integrals. The conversation highlights the importance of correctly applying substitution techniques in integral calculus.
dawn_pingpong
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Homework Statement


By using substitution u=\frac{1}{t}, or otherwise, show that

\int^∞_1 \frac{t^5}{(1+t^3)^3}dt=\int^1_0 \frac{u^2}{(1+u^3)^3}du

Homework Equations





The Attempt at a Solution


integral.png


Well, the reverse can also be done (making t to u). However, I don't know how to change the premise of the integral (from (∞,1) to (1,0). Thank you! I can integrate the integral after that.
 
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dawn_pingpong said:

Homework Statement


By using substitution u=\frac{1}{t}, or otherwise, show that

\int^∞_1 \frac{t^5}{(1+t^3)^3}dt=\int^1_0 \frac{u^2}{(1+u^3)^3}du

Homework Equations



The Attempt at a Solution


integral.png


Well, the reverse can also be done (making t to u). However, I don't know how to change the premise of the integral (from (∞,1) to (1,0). Thank you! I can integrate the integral after that.
\displaystyle \lim_{t\,\to\ \ \infty}\frac{1}{t}\ \ =\ \ \underline{\ \ ?\ \ }
 
0?

so the integral is just 0- \int\left[\frac{(1/t)^2}{t^2(1+(1/t)^3}\right]^1?(sorry don't really know how I'm supposed to write this...)

and at 0 the integral is 0. but it seems there is something wrong with the sign, because it is negative...
 
Last edited:
\displaystyle \int_a^b f(x)\,dx=- \int_b^a f(x)\,dx
 
oh right! thanks!
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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