Evaluating Divergence Thm: V, S & Verify for x^2+y^2+z^2=1

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SUMMARY

The discussion focuses on evaluating the divergence theorem for the vector field V = xi + yj + zk and the surface S defined by the sphere x^2 + y^2 + z^2 = 1. The divergence theorem states that the triple integral of the divergence of V over the volume V equals the double integral of V dot normal over the surface S. In this case, calculating the divergence of V is straightforward, while integrating V.n dS requires projecting the surface into the xy-plane and using polar coordinates for both the upper and lower hemispheres of the sphere.

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jlmac2001
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I need help evaluating both sides of the divergence theorem if V=xi+yj+zk and the surface S is the sphere x^2+y^2+z^2=1, and so verify the divergence theorem for this case.

Is the divergence theorem the triple integral over V (div V) dxdydz= the double integral over S (V dot normal)dS? If so I would I evaluate it for the above problem?
 
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Try looking these things up, (Wolfram/mathworld). And yes, verify means evaluate both sides of the equality.
 
Note that, in this problem, div V is very simple so the integration over the volume is trivial. Integrating V.n dS on the surface is a bit more challenging but if you "project" the surface into the xy-plane and then use polar coordinates, it should be easy. (Don't forget to do both the part of the sphere above the xy-plane and the part below!)
 

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