Evaluating double integral - jacobian help

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Homework Help Overview

The discussion revolves around evaluating a double integral using a coordinate transformation. The original poster is attempting to transform the integral involving the expression \([(x^2 + y^2)/1 + (x^2-y^2)^2]e^{-2xy}\) over the first quadrant, specifically from \(0\) to \(\infty\) for both variables.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the calculation of the Jacobian and the challenges in determining the new limits of integration after the transformation. There are inquiries about the nature of the curves for the new variables \(u\) and \(v\), particularly in relation to the first quadrant.

Discussion Status

Participants are actively engaging in exploring the limits of integration for the transformed variables. Some have suggested visualizing the region and contour lines to aid in understanding the new limits, while others are confirming the behavior of the curves in the transformed space.

Contextual Notes

There is a focus on the first quadrant and the implications of the transformation on the limits of integration, with specific mention of the behavior of hyperbolae in relation to the new variables. The discussion acknowledges the complexity of determining these limits when transitioning from Cartesian to the new coordinate system.

bon
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Homework Statement



trying to evaluate the double integral from 0 to infinity and 0 to infinity of [(x^2 + y^2)/1 + (x^2-y^2)^2]e^-2xy dxdy

using the coordinate transformation u=x^2-y^2 and v=2xy



Homework Equations





The Attempt at a Solution



so i calculated the jacobian which looks nice 4(x^2+y^2)..can see some canceling there

just can't see what the new limits will be...

thanks for any help
 
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Hi bon! :smile:

(have an infinity: ∞ and try using the X2 tag just above the Reply box :wink:)

When you're trying to find new 2D or 3D limits, just draw the region, and then mark it with the "contour lines" of the new variables.

In this case, the region is the whole first quadrant …

now draw some typical curves for u = constant and for v = constant …

check that (u,v) is single-valued, and just read off the diagram what the lowest and highest "contour lines" are. :wink:
 


Ok thanks so i see that v goes from 0 to infinity...i just can't see u at the moment..

thanks
 
u = 0 is the straight diagonal line …

what are the other curves for u = constant in the first quadrant? :wink:
 


ahh hyperbolae..so would it be -infinity to + infinity?

thanks
 


is this right?
 
bon said:
ahh hyperbolae..so would it be -infinity to + infinity?

thanks

let's see …

each lower "hyperbola" is a quarter of a hyperbola, starting at the x-axis and finishing "at infinity", close to the diagonal …

so it goes from xy = 0 to xy = ∞ (and the same for the upper "hyperbolas").

So yes, x2 - y2 goes from -∞ to ∞, and for each value of x2 - y2, xy goes from 0 to ∞. :smile:
 


great thanks
 

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