Evaluating Improper Integral - ∫[(1)/(3x+1)^2] dx

[Mathematics07]

[\The question is to evaluate the integral from 1 to infinity of ∫[(1)/(3x+1)^2] dx.


No idea how to do this can anyone help explain improper integrals please.

THE ANSWER TO THE PROBLEM IS 1/12 thought . . . .

Thanks

 

[Feldoh]

You need to find the anti-derivative and then evaluate it the anti derivative like normal, just take the limit as the upper limit of integration goes to infinity.

 

[dextercioby]

To find that antiderivative, just substitute ' 3x +1 = p ' and then express the whole deal in terms of ' p ' .