Evaluating \int e^{2x^2}dx using the equation \frac{e^{2x^2}}{4x}+c

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SUMMARY

The integral of the function \(\int e^{2x^2}dx\) does not have an elementary antiderivative. The proposed solution \(\frac{e^{2x^2}}{4x}+c\) is incorrect, as differentiating it using the quotient rule introduces an extraneous term. Instead, utilizing the Maclaurin series for \(e^{2x^2}\) allows for term-by-term integration, providing a valid approach to evaluate the integral.

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Homework Statement



[tex]\int e^{2x^2}dx[/tex]

Homework Equations





The Attempt at a Solution



i found [tex]\frac{e^{2x^2}}{4x}+c[/tex]

correct ?
 
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Not correct. Try differentiating your proposed solution to see if it gives back what you started with. When you apply the quotient rule, you will see that one term gives what you want, but there will be an extra term
 
And furthermore, the integral you show doesn't have an elementary antiderivative. If you know about Maclaurin series, though, you can write the Maclaurin series for e2x2, and then integrate it term by term.
 

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