Evaluating the location r_m of the minimum of potential

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The discussion centers on finding the location of the minimum potential in a model of neutral atoms as an ideal gas. The potential function V(r) is derived from the Lennard-Jones potential, and its minimum corresponds to the equilibrium position of the system. To locate the minimum, the force F(r) is determined by differentiating V(r) and setting it to zero. The participants clarify that the location r_m of the minimum is found when the derivative expression equals zero. Understanding these concepts is essential for analyzing the behavior of the gas system at equilibrium.
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Homework Statement


A gas of neutral atoms is often modeled as an ideal gas, where the gas atoms are considered to be "elastic billiard balls" that only interact by bouncing off each other in a manner that conservers the total kinetic energy.

Homework Equations


V(r) = 4(Epsilon)[(delta/r)^12 - (delta/r)^6]

in dimensionless form
U(xi) = 4 [(1/xi)^12 - (1/xi)^6]

xi= delta/r, U = V(r)/epsilon

The Attempt at a Solution


so i differentiated V(r) to get F(r),since F(r) = - dV(r)/dr.The force at the minimum of the potential is zero and the potential minimum defines the equilibrium position of the system.
 
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Generally speaking, you can find the extrema (minimum, maximum, saddle point) of any function f(x) by calculating when its derivative is 0. You don't need to invoke the force here.
 
my question was how do i evaluate the location of r_m of the minimum potential.
 
Like this:
tasleem moossun said:
The force at the minimum of the potential is zero and the potential minimum defines the equilibrium position of the system.
 
so basically the location of r_m would be -4(epsilon)[(-12(delta^12)/r^13 + 6delta^6/r^7]
 
No, it is the r where this expression is zero.
 
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