Evaluating the location r_m of the minimum of potential

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Homework Statement


A gas of neutral atoms is often modeled as an ideal gas, where the gas atoms are considered to be "elastic billiard balls" that only interact by bouncing off each other in a manner that conservers the total kinetic energy.

Homework Equations


V(r) = 4(Epsilon)[(delta/r)^12 - (delta/r)^6]

in dimensionless form
U(xi) = 4 [(1/xi)^12 - (1/xi)^6]

xi= delta/r, U = V(r)/epsilon

The Attempt at a Solution


so i differentiated V(r) to get F(r),since F(r) = - dV(r)/dr.The force at the minimum of the potential is zero and the potential minimum defines the equilibrium position of the system.
 
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Generally speaking, you can find the extrema (minimum, maximum, saddle point) of any function f(x) by calculating when its derivative is 0. You don't need to invoke the force here.
 
my question was how do i evaluate the location of r_m of the minimum potential.
 
Like this:
tasleem moossun said:
The force at the minimum of the potential is zero and the potential minimum defines the equilibrium position of the system.
 
so basically the location of r_m would be -4(epsilon)[(-12(delta^12)/r^13 + 6delta^6/r^7]
 
No, it is the r where this expression is zero.
 
To solve this, I first used the units to work out that a= m* a/m, i.e. t=z/λ. This would allow you to determine the time duration within an interval section by section and then add this to the previous ones to obtain the age of the respective layer. However, this would require a constant thickness per year for each interval. However, since this is most likely not the case, my next consideration was that the age must be the integral of a 1/λ(z) function, which I cannot model.

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