Exact Differential Equation and Green's theorem

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We can use Green's theorem to understand why the Exact Differential Equation satisfy the conditions it should have ...

How about a DE for more than two variables ?

Eg.dF=P(x,y,z,w)dx+Q(x,y,z,w)dy+R(x,y,z,w)dz+S(x,y,z,w)dw

IF the equation above is an Exact Differential Equation , what condition it would satisfy ?
 
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An equation of the form f(x,y,z)dx+ g(x,y,z)dy+ h(x,y,z)dz= 0 is "exact" if and only if there exist some F(x,y,z) such that
dF= \frac{\partial F}{\p<br /> artial x}dx+ \frac{\partial F}{\partial y}dy+ \frac{\partial F}{\partial z}= f(x,y,z)dx+ g(x,y,z)dy+ h(x,y,z)dz

That means that we must have
\frac{\partial F}{\partial x}= f(x,y,z)
\frac{\partial F}{\partial y}= g(x,y,z)
and
\frac{\partial F}{\partial z}= h(x,y,z)

So, as long as those functions are continuous, we must have the "mixed partials" equal:
\frac{\partial^2 F}{\partial x\partial y}= \frac{\partial f}{\partial y}= \frac{\partial g}{\partial x}= \frac{\partial^2 F}{\partial y\partial x}
etc.

Since you mention "Green's theorem" (for two variables) you might want to look at \nabla\times f(x,y,z)\vec{i}+ g(x,y,z)\vec{j}+ h(x,y,z)\vec{k} and Stoke's theorem.
 
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What u mentioned contains three variables ~and I've seen such a case in the book I read...

Suppose \vec{F}=P(x,y,z)\hat{i}+Q(x,y,z)\hat{j}+R(x,y,z)\hat{k}

dT=P(x,y,z)dx+Q(x,y,z)dy+R(x,y,z)dz is exact if only if \vec{F}\bullet(\nabla\times\vec{F})=0

I'm now requesting for the case which contains more than three variables~


HallsofIvy said:
An equation of the form f(x,y,z)dx+ g(x,y,z)dy+ h(x,y,z)dz= 0 is "exact" if and only if there exist some F(x,y,z) such that
dF= \frac{\partial F}{\partial x}dx+ \frac{\partial F}{\partial y}dy+ \frac{\partial F}{\partial z}= f(x,y,z)dx+ g(x,y,z)dy+ h(x,y,z)dz

That means that we must have
\frac{\partial F}{\partial x}= f(x,y,z)
\frac{\partial F}{\partial y}= g(x,y,z)
and
\frac{\partial F}{\partial z}= h(x,y,z)

So, as long as those functions are continuous, we must have the "mixed partials" equal:
\frac{\partial^2 F}{\partial x\partial y}= \frac{\partial f}{\partial y}= \frac{\partial g}{\partial x}= \frac{\partial^2 F}{\partial y\partial x}
etc.

Since you mention "Green's theorem" (for two variables) you might want to look at \nabla\times f(x,y,z)\vec{i}+ g(x,y,z)\vec{j}+ h(x,y,z)\vec{k} and Stoke's theorem.
 
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