Example of dense non surjective operator

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SUMMARY

An example of a bounded operator on a Hilbert space with a dense range but not surjective is the mapping from \(\ell_1\) (the space of absolutely summable sequences) to \(L_2[0, 2\pi)\) (the space of complex-valued square integrable functions on the interval [0, 2π)). This operator is defined by the transformation \((a_n) \mapsto \sum a_n \exp(\sqrt{-1} n x)\). The open mapping theorem confirms that while the operator has a dense range, it does not achieve surjectivity.

PREREQUISITES
  • Understanding of bounded operators in functional analysis
  • Familiarity with Hilbert spaces, specifically \(\ell_1\) and \(L_2\) spaces
  • Knowledge of the open mapping theorem
  • Basic concepts of Fourier series and transformations
NEXT STEPS
  • Study the properties of bounded operators in Hilbert spaces
  • Learn about the open mapping theorem and its implications
  • Explore the relationship between \(\ell_1\) and \(L_2\) spaces
  • Investigate examples of non-surjective operators in functional analysis
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Mathematicians, students of functional analysis, and anyone interested in the properties of bounded operators and Hilbert spaces.

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Hi, can anyone give me an example of a bounded operator on a Hilbert space that has dense range but is not surjective? (Preferably on a separable Hilbert space)

Im pretty sure such an operator exists since the open mapping theorem requires surjectivity and not just dense range, but its just bothering me that I can't find an example.
 
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How about \ell_1 (all absolutely summable sequences) being mapped into L_2[0, 2\pi) ( all complex valued square integrable functions on [0, 2\pi) ) by

(a_n) -> \sum a_n \exp( \sqrt{-1} n x)
 

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