Expectation of X^Y: Estimator & Calculation

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The discussion centers on calculating the expectation of X raised to the power of Y, where X and Y are independent and identically distributed random variables. A participant suggests that E(X^Y) could equal E(X)^E(Y) under certain conditions, particularly when variances are small. However, others argue that this assumption may not hold true, pointing out that specific examples, such as uniformly distributed variables, can lead to nonsensical results. The consensus leans towards the idea that small variances alone are insufficient for the proposed equality to be valid. The conversation highlights the complexity of expectations involving random variables and the need for careful consideration of their distributions.
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Can anyone let me know the estimator for the expectaiion of X^Y. X and Y are iid random variables, and their expectation are E(X) and E(Y) respectively.

Thank you.
 
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I'm pretty sure that's not enough information.
 
Okay, let me put this way. Let E(X) be the expectation of random variable X, and X and Y are independent and identically distributed random variables. My question is, what is E(X^Y)? I did Talyor expansion of X^Y and concluded that, for small variances for X and Y, E(X^Y)=E(X)^E(Y).

Is this correct?
Thank you for your help in advance.
 
It's (probably) true that if the distributions of X and Y are "close" to constant, then then E(X^Y)=E(X)^E(Y) is approximately true.

My gut says that small variances isn't enough, but I haven't done the calculations to be sure.
 
I believe it is not true. Try a simple particular case. For example assume X and Y are uniformly distributed over some interval, and work out E(XY).
A good crazy example would use two intervals symmetrical around 0 (avoid 0 itself), then E(X)E(Y) would be 00, which would be nonsense.
 
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