Expert Witness Testimony: Accident Analysis

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SUMMARY

The discussion centers on calculating the impact speed of car A when it slid into car B at a red light, considering two different coefficients of kinetic friction. For part (a), with a coefficient of 0.60 on a dry road, the correct speed at impact is 5.476 m/s, but the calculation must also account for the slope of the hill at θ = 12.0°. The initial speed of car A was 17.5 m/s, and the distance between the cars was 23.5 m. The user initially neglected the slope, which affects the acceleration due to gravity.

PREREQUISITES
  • Understanding of Newton's second law of motion (∑F = ma)
  • Knowledge of kinematic equations (v² = v₀² + 2aΔx)
  • Familiarity with the concepts of friction and its coefficients
  • Basic trigonometry to account for slope effects
NEXT STEPS
  • Calculate the impact speed of car A considering the slope of the hill using the adjusted acceleration.
  • Explore the effects of different coefficients of friction on stopping distances in various conditions.
  • Learn about the role of anti-lock braking systems (ABS) in vehicle dynamics.
  • Investigate the physics of collisions and momentum conservation principles.
USEFUL FOR

Physics students, accident reconstruction experts, and automotive safety analysts will benefit from this discussion, particularly those focusing on vehicle dynamics and collision analysis.

InsTanCeZ
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Homework Statement



You testify as an "expert witness" in a case involving an accident in which car A slid into the rear of car B, which was stopped at a red light along a road headed down a hill. You find that the slope of the hill is θ = 12.0°, that the cars were separated by distance d = 23.5 m when the driver of car A put the car into a slide (it lacked any automatic anti-brake-lock system), and that the speed of car A at the onset of braking was v0 = 17.5 m/s.

(a) With what speed did car A hit car B if the coefficient of kinetic friction was 0.60 (dry road surface)?

(b) What was the speed if the coefficient of kinetic friction was 0.10 (road surface covered with wet leaves)?

Homework Equations



∑F = ma = μmg

v² = v₀² + 2aΔx

The Attempt at a Solution



∑F = ma = μmg
a = μg
= 0.600(-9.80m/s²)
= -5.88m/s²

v² = v₀² + 2aΔx
= (17.5m/s)² + 2(-5.88m/s²)(23.5m)
= 5.476m/s (part a)

haven't tried part b

How is this wrong? My online homework said 5.467 wasn't the answer for part a.
 
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InsTanCeZ said:

Homework Statement



You testify as an "expert witness" in a case involving an accident in which car A slid into the rear of car B, which was stopped at a red light along a road headed down a hill. You find that the slope of the hill is θ = 12.0°, that the cars were separated by distance d = 23.5 m when the driver of car A put the car into a slide (it lacked any automatic anti-brake-lock system), and that the speed of car A at the onset of braking was v0 = 17.5 m/s.

(a) With what speed did car A hit car B if the coefficient of kinetic friction was 0.60 (dry road surface)?

(b) What was the speed if the coefficient of kinetic friction was 0.10 (road surface covered with wet leaves)?

Homework Equations



∑F = ma = μmg

v² = v₀² + 2aΔx

The Attempt at a Solution



∑F = ma = μmg
a = μg
= 0.600(-9.80m/s²)
= -5.88m/s²

v² = v₀² + 2aΔx
= (17.5m/s)² + 2(-5.88m/s²)(23.5m)
= 5.476m/s (part a)

haven't tried part b

How is this wrong? My online homework said 5.467 wasn't the answer for part a.
It has to to do with you neglecting the slope of the road.
 
Thanks, I figured it out. :)
 

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