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I have the range and the expression for the range. If my work is correct, as attached, until hitherto, I'm having problem finding vi or Θ.Can you elaborate on your work and what exactly you're getting hung up on?
I suppose that would be a reasonable premise from which I can work on. It should be solvable then.Based on the structure of the question I would assume that, they don't intend for you actually find the exact speed they were travelling. So I would just start by assuming they were going 60km/h and see if that would cause them to travel 39m.
That's strange. I was only able to deduce the angle, assuming the entity was travelling at 60kmh^-1 and landed 39m from point of collision, at which the entity was flung upon collision.Based on the structure of the question I would assume that, they don't intend for you actually find the exact speed they were travelling. So I would just start by assuming they were going 60km/h and see if that would cause them to travel 39m.
You don't know the angle of launch (θ).1. Homework Statement
As an expert witness, you're testifying in a case involving a motorcycle accident. A motorcyclist driving in a 60km/h zone hit a stopped car on a level road. The motorcyclist was thrown from his bike and landed 39m down the road.
Was he speeding?
3. The Attempt at a Solution
View attachment 66096
I didn't notice the first half of the attachment were work from another question.You don't know the angle of launch (θ).
What's the formula for range? How would you find the maximal range from that formula (hint: max value of sine)?
Now see what the max range for a v_{i} of 60km/h is.
If θ = 45 degrees, what is 2θ and therefore sin 2θ in the formula? Is this the maximum value of the sine function?Edit: Sine 45? It did occurred to me but in theory, would it be reasonable to assume the entity is flung at an angle of 45 degrees?
I did further work 2 posts earlierIf θ = 45 degrees, what is 2θ and therefore sin 2θ in the formula? Is this the maximum value of the sine function?
You're not saying he was definitely flung at that angle. You're saying that this (45 degrees) is the angle that maximises range at any initial velocity. If he was going at the limit, even this maximal range would fall short of how far he was actually propelled. Hence, what can you conclude?
This post is basically right, except for a couple of typos. You computed the minimum velocity that he would actually have had to be travelling at in order to achieve that range. Not strictly necessary, but good to know. Note that he could well have been travelling faster than this (in which case his launch angle might have been lower or higher than 45 degrees).Another hypothesis:
If I assume launched angle is 45° and initial velocity = [itex] 16.67ms^-1[/itex]
and
x = [itex]\frac{2vi^2 cosΘsinΘ}{g}[/itex]
then [itex]16.68ms^-1 cos 45° \frac{16.68 sin 2(45°)}{9.8ms^-2}[/itex]
= 28m
Given the above parameter, the displacement is 28m
Therefore, given the same launch angle of 45°, the only possible solution for the entity to be flung at a displacement > 28m is for the initial velocity to be [itex] > 16.67ms^-1 [/itex]
Hence, it can be deduced that the entity was speeding.
and given the entity achieved a displacement of 39m and suppose we further assume the launch angle is 45 degrees, the initial velocity works out to be 19.6ms^-1 and 1.96ms^-1 > 16.67ms^-1.