Exploring Momentum Conservation in a Falling Ball and Earth System

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Momentum conservation in a falling ball and Earth system is illustrated by the ball's momentum increasing downward while the Earth's momentum increases upward, maintaining overall conservation. Upon collision with the ground, the ball's momentum change is 2mv, prompting questions about the Earth's momentum change. The Earth's change in momentum is calculated as 2M_earthV_earth, equating to the ball's momentum change. This implies that the Earth experiences a negligible upward motion in response to the collision. Thus, momentum is conserved in the entire system despite the apparent change in direction of the ball.
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Momentum conservation?

Consider a ball falling towards the earth. I understand here how momentum is conserved here (ball momentum increases in one direction and Earth momentum increases in the other).
BUT when the ball collides with the floor and it changes direction its momentum change is 2mv. How is momentum consereved in the whole system?
 
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The Earth collided with the ball too :wink:
 


Infinitum said:
The Earth collided with the ball too :wink:
so do you mean the Earth's change in momentum is 2mv?
 


The change in Earth's momentum is

2M_{earth}V_{earth}

Where Vearth is the original velocity with which the Earth was moving(neglecting rotation/revolution), and that is equal to 2mv.
 
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Infinitum said:
The change in Earth's momentum is

2M_{earth}V_{earth}

Where Vearth is the original velocity with which the Earth was moving, and that is equal to 2mv.

ok so to check that means the Earth is moving DOWNWARD (however negligible the motion)
 


Pretty much, yes. Though downward isn't exactly defined in this sense. More appropriate to say Earth is moving opposite to the original direction of motion, assuming the collision was head-on.
 
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