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I already know some of these variables, but I am not fully sure I get every effect of them and I still don't understand the importance of RPM.Lnewqban said:Yes, you will be able.
Yes, that is the principle of a flywheel.
Your flywheel is solidly connected to a motor that can't be just pop out of existence.
The flywheel will rotate a little slower after shooting the ball, it will try to slowdown the motor, which will react applying a torque to speed up the flywheel until reaching the motor nominal rpm's.
The case is similar to a car trying to reach a high speed in first gear: the wheels receive lots of torque, but are unable to spin faster.
If we increase the mass of the wheel instead of velocity, our machine will be able to shoot heavier balls at the same velocity.
If no connected to a source of energy (the electrical motor in this case), the flywheel will have less momentum after giving some of it away to each launched ball.
As the mass of the flywheel can't be reduced, a reduction in rotational velocity will be the result of a free spinning flywheel launching several balls successively.
Yes.
Please, see:
http://hyperphysics.phy-astr.gsu.edu/hbase/mi.html#rlin
http://hyperphysics.phy-astr.gsu.edu/hbase/mi.html#c2
http://hyperphysics.phy-astr.gsu.edu/hbase/rotq.html
http://hyperphysics.phy-astr.gsu.edu/hbase/amom.html#am
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about the wheel imagine instead I spin it up and then disengage it so that it is spinning freely without any resistance but isn't accelerating and applying a force anymore.
since you use a car metaphor I'll try to use one too: imagine we lift a car up in the air and accelerate it, and a certain point we just disengage the engine so it isn't powering the car anymore, while the wheels still roll we let the car down on the ground. at this point the car should start moving, but the question is why, how does the RPM of the car determine how fast it moves (how much force it applies on the ground)