Exponential decay word problem (check work)

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The initial amount of hydrocodone bitartrate taken is 10 mg. Each hour, 18% of the drug leaves the body. After 6 hours, approximately 3.04 mg of the drug remains. It takes about 11.6 hours for only 1 mg of the drug to remain in the body. The calculations provided are confirmed to be correct, though showing all work would enhance clarity.
Jacobpm64
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At time t hours after taking the cough suppressant hydrocodone bitartrate, the amount, A, in mg, remaining in the body is given by A = 10(0.82)t.

(a) What was the intial amount taken?

10 mg

(b) What percent of the drug leaves the body each hour?

18%

(c) How much of the drug is left in the body 6 hours after the dose is administered?

A = 10(0.82)6
A = 3.04 mg

(d) How long is it until only 1 mg of the drug remains in the body?

1 = 10(0.82)t
1/10 = 0.82t
ln (1/10) = t ln0.82
t = ln (1/10) / ln0.82
t = 11.6028 hours

Are these correct?
 
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Certainly looks correct. It would help if one shows all work, e.g. on problem b, but the answer is correct.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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