- #1
Askhwhelp
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With mean = 2 with exponential distribution
Calculate
E(200 + 5Y^2 + 4Y^3) = 432
E(200) = 200
E(5Y^2) = 5E(Y^2) = 5(8) = 40
E(4Y^3) = 4E(Y^3) = 4(48) = 192
E(Y^2) = V(Y) + [E(Y)]^2 = 2^2+2^2= 8
E(Y^3) = m_Y^3(0) = 48(1-2(0))^{-4} = 48
is this right?
Calculate
E(200 + 5Y^2 + 4Y^3) = 432
E(200) = 200
E(5Y^2) = 5E(Y^2) = 5(8) = 40
E(4Y^3) = 4E(Y^3) = 4(48) = 192
E(Y^2) = V(Y) + [E(Y)]^2 = 2^2+2^2= 8
E(Y^3) = m_Y^3(0) = 48(1-2(0))^{-4} = 48
is this right?