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Exponential distribution moment generating function to find the mean

  1. Dec 7, 2013 #1
    With mean = 2 with exponential distribution

    Calculate

    E(200 + 5Y^2 + 4Y^3) = 432

    E(200) = 200

    E(5Y^2) = 5E(Y^2) = 5(8) = 40

    E(4Y^3) = 4E(Y^3) = 4(48) = 192

    E(Y^2) = V(Y) + [E(Y)]^2 = 2^2+2^2= 8

    E(Y^3) = m_Y^3(0) = 48(1-2(0))^{-4} = 48

    is this right?
     
  2. jcsd
  3. Dec 7, 2013 #2
    Please take a look of this
     
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