Exponential distribution moment generating function to find the mean

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SUMMARY

The discussion focuses on calculating the expected value of a function involving an exponential distribution with a mean of 2. The calculations provided include E(200 + 5Y^2 + 4Y^3) resulting in 432, with individual components calculated as E(200) = 200, E(5Y^2) = 40, and E(4Y^3) = 192. The variance and expected values for Y^2 and Y^3 are derived using the formulas E(Y^2) = V(Y) + [E(Y)]^2 = 8 and E(Y^3) = 48, confirming the accuracy of the calculations presented.

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With mean = 2 with exponential distribution

Calculate

E(200 + 5Y^2 + 4Y^3) = 432

E(200) = 200

E(5Y^2) = 5E(Y^2) = 5(8) = 40

E(4Y^3) = 4E(Y^3) = 4(48) = 192

E(Y^2) = V(Y) + [E(Y)]^2 = 2^2+2^2= 8

E(Y^3) = m_Y^3(0) = 48(1-2(0))^{-4} = 48

is this right?
 
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