Ok, so I have an unknown exponential function:
y1 = f1(t)
By measuring the values of t and yi, a linear connection is generated between Yi (=log (yi)) and t:
Yi = Ait + Bi.
A1 = -2.12
B1 = 1.96
Problem 1: Describe f1 in the following matter:
y1 = f1(t) = Ceλt
The Attempt at a Solution
I've been juggling with numbers and letters without ending up with anything reasonable.
Ok, let's ramble down some thoughts:
Adding log function to both sides of the functions gives
log(y1) = log t + log -2.12 + log 1.96 = log (C) + log (e) λt
And this is where it all ends. Any help out there? Would be much appreciated!