- #1
carbz
- 35
- 0
Please note, there are more questions than what I'm going to give, in total I'll be giving 3. I hope to use the information with the others.
1)
Solve the equation:
[tex]5^{1-2x} = \frac{1}{5}[/tex]
None
I was thinking that to make live easier, to put the entire fraction up to the first power. From there, I would use algebra in the sense of:
[tex]1-2x=1[/tex]
[tex]-2x=0[/tex]
To get x = 0. But, that doesn't seem to be possible, since the exponent must turn out to be negative.
2)
Solve the Equation:
[tex]8^{x^{2} - 2x}} = \frac{1}{2}[/tex]
None
For this one, I was thinking of setting the fraction equal to 1, then factoring that out to get two answers:
[tex]x^2 - 2x = 1[/tex] [tex]x^2 - 2x - 1 = 0[/tex]
But, then I'm stuck there.
3)
Solve the equation:
[tex]e^{x^2} = (e^{3x})(\frac{1}{e^2})[/tex]
None
I'm completely clueless on this one.
1)
Homework Statement
Solve the equation:
[tex]5^{1-2x} = \frac{1}{5}[/tex]
Homework Equations
None
The Attempt at a Solution
I was thinking that to make live easier, to put the entire fraction up to the first power. From there, I would use algebra in the sense of:
[tex]1-2x=1[/tex]
[tex]-2x=0[/tex]
To get x = 0. But, that doesn't seem to be possible, since the exponent must turn out to be negative.
2)
Homework Statement
Solve the Equation:
[tex]8^{x^{2} - 2x}} = \frac{1}{2}[/tex]
Homework Equations
None
The Attempt at a Solution
For this one, I was thinking of setting the fraction equal to 1, then factoring that out to get two answers:
[tex]x^2 - 2x = 1[/tex] [tex]x^2 - 2x - 1 = 0[/tex]
But, then I'm stuck there.
3)
Homework Statement
Solve the equation:
[tex]e^{x^2} = (e^{3x})(\frac{1}{e^2})[/tex]
Homework Equations
None
The Attempt at a Solution
I'm completely clueless on this one.
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