CathyLou
- 173
- 1
Hi.
Could someone please explain to me the following C3 level question? I would really appreciate any help as I am completely stuck at the moment.
Given that y = arccos x, -1 <= x <= 1 and 0 <= y <= pi,
(a) express arcsin x in terms of y.
I have written down that x = cos y but I do not know where to go from here. It says on the markscheme that:
x = sin (pi/2 - y) which leads to arcsin x = pi/2 - y
arcsinx = arcsin cos y
but I do not understand why this is the case. Could someone please help with this and part (b) of the question also?
(b) Hence evaluate arccos x + arcsin x. Give your answer in terms of pi.
Thank you.
Cathy
Could someone please explain to me the following C3 level question? I would really appreciate any help as I am completely stuck at the moment.
Given that y = arccos x, -1 <= x <= 1 and 0 <= y <= pi,
(a) express arcsin x in terms of y.
I have written down that x = cos y but I do not know where to go from here. It says on the markscheme that:
x = sin (pi/2 - y) which leads to arcsin x = pi/2 - y
arcsinx = arcsin cos y
but I do not understand why this is the case. Could someone please help with this and part (b) of the question also?
(b) Hence evaluate arccos x + arcsin x. Give your answer in terms of pi.
Thank you.
Cathy