Extracting Vector F: A General Question

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Homework Help Overview

The discussion revolves around the extraction of a vector field F given that the curl of F equals a constant vector B. Participants are exploring the implications of this relationship in the context of vector calculus.

Discussion Character

  • Conceptual clarification, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Some participants question whether F must be a vector field and discuss the conditions under which the curl operator applies. Others explore the mathematical formulation of the curl and its implications for solving for F, noting that the system of equations derived from the curl may have multiple solutions.

Discussion Status

The discussion is ongoing, with participants providing insights into the nature of vector fields and the uniqueness of solutions. There is recognition that multiple vector fields can satisfy the condition of having a curl equal to a constant vector, indicating a productive exploration of the topic.

Contextual Notes

Participants note that there is no unique solution to the problem, as many vector fields can yield a curl of zero. This introduces considerations about the nature of the vector field F and the constraints imposed by the problem.

M.M.M
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Hi everybody ...


I have a general question ..


if i have for example...

curl F = B

F and B are vectors and B is constant vector ..

is there any way to extract vector F?

thanks
 
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Must F be a vector field F = F_{x}\widehat{i} + F_{y}\widehat{j} + F_{z}\widehat{k}+...? I thought \nabla \times F only operates if F is a vector field.
 
Yes, that's true. He said "vector F" several times.

\nabla\times F= \left(\frac{\partial F_y}{\partial z}- \frac{\partial F_z}{\partial y}\right)\vec{i}- \left(\frac{\partial F_x}{\partial z}- \frac{\partial F_z}{\partial x}\right)\vec{j}+ \left(\frac{\partial F_y}{\partial x}- \frac{\partial F_x}{\partial y}\right)\vec{k}
so that would be essentially solving the system of equations
\frac{\partial F_y}{\partial z}- \frac{\partial F_z}{\partial y}= B_x
\frac{\partial F_x}{\partial z}- \frac{\partial F_z}{\partial x}= B_y
\frac{\partial F_y}{\partial x}- \frac{\partial F_x}{\partial y}= B_z

Since we can think of the cross product of two vectors as giving a vector perpendicular to both, that system, and the original equation, has a solution only if B is "perpendicular" to the "vector" \nabla", that is if div B= \nabla\cdot B= 0.
 
M.M.M said:
Hi everybody ...


I have a general question ..


if i have for example...

curl F = B

F and B are vectors and B is constant vector ..

is there any way to extract vector F?

thanks

There's no unique solution since there are a lot of vector fields with curl zero. If you just want anyone try messing around with linear functions of the coordinates, like F=(0,a*x,b*x+c*y).
 

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