Extremely different integral problem

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SUMMARY

The discussion focuses on calculating the area A as a function of j for the region in the first quadrant bounded by the y-axis and the curves y = x^(1/3) and y = j, where j > 0. The solution involves setting x = j^3, leading to the area A(j) being defined as the integral of (j - x^(1/3)) dx from 0 to j^3. This integral formulation is essential for determining the area based on the parameter j.

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Homework Statement


(a) Find the area A, as a function of j, of the region in the 1st quadrant enclosed by the y-axis and the graphs of y = x ^ (1/3) and y = j for j > 0.


2. The attempt at a solution

(a)
x^(1/3) = j
x = j^3

A(j) = integral of (j - x^(1/3))dx from 0 to j^3

Any help would be much appreciated! :)

Thanks
 
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I'd begin by writing down the equation of the Area, so that I can plug in the parameter j and get a number which is the Area.

Just do it, then...
 

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