Extremely easy math, but need expression

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The discussion revolves around solving a sequence of coordinate points where the first point (X1) is derived by subtracting a specific value, and subsequent points (X2, X3, X4, X5, X6) are calculated by consistently subtracting a fixed amount from the previous point. Participants confirm that this scenario represents an arithmetic progression, where the difference between terms remains constant. A formula for this sequence is provided: Tn = a + (n-1)d, where 'a' is the first term and 'd' is the common difference. The conversation emphasizes the simplicity of the arithmetic progression concept in solving the problem. Overall, the thread offers clarity on applying basic mathematical principles to coordinate point calculations.
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Okay,
This could be the easiest math question on here... but I'm going to ask the dumb question anyway. I have several coordinate points to solve for, and in each case I subtract the same amount from the previous "x" to get the next "x" value (X2...3...4...5...). The only point where I subract a different value is X1. The rest have a constant rate of change (derivative?). Example:

1.) X1 = (some vaule) – 30’
2.) X2 = (X1 – 60’), X3 = (X2 – 60’), X4 = (X3 – 60’), X5 = (X4 – 60’), X6 = (X5 – 60’)

There has to be a simple mathematical formula, other than this sloppy one. Any help would be great.
 
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like Mark44 said this is an arithmetic progression
Here the difference between two terms(of the sequence) is equal
Tn=a+(n-1)d
where a is the first term and d is the difference between two terms(d=T2-T1)
 
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