Factoring Help, Finding two variables

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Homework Help Overview

The problem involves finding the values of the variables m and g in the polynomial function f(x) = mx^3 + gx^2 - x + 3, given specific remainders when the function is divided by x - 1 and x + 3. The context is rooted in polynomial division and the Remainder Theorem.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the setup of equations derived from the Remainder Theorem, questioning the correctness of their calculations and the resulting fractions. There is an exploration of potential mistakes in the equations formed from the remainders.

Discussion Status

Participants are actively engaging with the problem, identifying errors in their previous calculations and discussing the implications of these errors. Some guidance is offered regarding the equations that need to be solved, but there is no explicit consensus on the correct approach or resolution yet.

Contextual Notes

There is mention of confusion regarding the signs and values in the equations derived from the polynomial division, as well as concerns about the feasibility of obtaining certain factors based on the resulting equations.

Emperor
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Homework Statement



If f(x) = mx^3 + gx^2 - x + 3 is divided by x - 1, the remainder is 3. If f(x) is divided by x + 3, the remainder is -1. What are the values of m and g?

Homework Equations



Remainder Theorum/Factor Theorum

The Attempt at a Solution



Here is what I did:

f(x)=mx^3+gx^2-x+3

x -1 remainder = 3

3=m(1)^3+g(1)^2-(1)+3
3=m+g-1+3
1=m+g

x + 3, remainder = -1

-7=m(-3)^3+g(-3)^2-(-3)+3
-7=-27m+9g+3+3
-----------------------

Past that point is where I start getting fractions to my answers which don't lead me anywhere close to my answer. Where did I make a mistake and how can I solve it?
 
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Emperor said:

Homework Statement



If f(x) = mx^3 + gx^2 - x + 3 is divided by x - 1, the remainder is 3. If f(x) is divided by x + 3, the remainder is -1. What are the values of m and g?

Homework Equations



Remainder Theorum/Factor Theorum

The Attempt at a Solution



Here is what I did:

f(x)=mx^3+gx^2-x+3

x -1 remainder = 3

3=m(1)^3+g(1)^2-(1)+3
3=m+g-1+3
1=m+g

x + 3, remainder = -1

-7=m(-3)^3+g(-3)^2-(-3)+3
-7=-27m+9g+3+3
-----------------------

Past that point is where I start getting fractions to my answers which don't lead me anywhere close to my answer. Where did I make a mistake and how can I solve it?

Shouldn't those -7's be -1's? And I think the (small) fractions you get will work.
 
LCKurtz said:
Shouldn't those -7's be -1's? And I think the (small) fractions you get will work.

Yeah, I messed up the equation:

-1=m(-3)^3+g(-3)^2-(-3)+3
-1=-27m+9g+3+3

collect like terms:

-7=-27m+9g

-1=(-27/7)n - (-9/7)g

As you can see I end up with some strange numbers. I never got the correct answer with them so I assume they're wrong. And yet, there's no possible way I can get a -9 or even a -3 to factor those numbers.
 
Last edited:
Emperor said:
Yeah, I messed up the equation:

-1=m(-3)^3+g(-3)^2-(-3)+3
-1=-27m+9g+3+3

collect like terms:

-7=-27m+9g

-1=(-27/7)n - (-9/7)g

As you can see I end up with some strange numbers. I never got the correct answer with them so I assume they're wrong. And yet, there's no possible way I can get a -9 or even a -3 to factor those numbers.

You have ##m+g=1## and ##-27m+9g = -7##. Two equations and two unknowns. Just solve them.
 

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