1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Factorization and Simplifying.

  1. Aug 24, 2011 #1
    1. The problem statement, all variables and given/known data
    Use Factorization to simplify the given expression.


    2. Relevant equations
    (x^3 + 3x^2 + 3x +1)/(x^4 + x^3 + x + 1)


    3. The attempt at a solution
    I cant get to the first step. I forgot how to factor exponents higher than x^2.
     
  2. jcsd
  3. Aug 24, 2011 #2

    LCKurtz

    User Avatar
    Science Advisor
    Homework Helper
    Gold Member

    Think about the binomial expansion of (a+b)3. Also you can check for roots using synthetic division. And remember a root x = r corresponds to a factor of x-r.
     
  4. Aug 24, 2011 #3
    Theorem of the factor.

    You can probably simplify the upper and the lower part, maybe even cancel out some stuff...
     
  5. Aug 24, 2011 #4
    But how to do that is the problem.
     
  6. Aug 24, 2011 #5

    Dick

    User Avatar
    Science Advisor
    Homework Helper

    If x=(-1) then the numerator and denominator are both 0. That means (x-(-1))=(x+1) is a common factor of the numerator and denominator. Now start factoring it out.
     
  7. Aug 25, 2011 #6

    NascentOxygen

    User Avatar

    Staff: Mentor

    As others have pointed out, x=-1 is a "solution" to the numerator (equaling zero). So this tells you that (x+1) is a factor of the numerator. So what is the other factor?

    If you don't like doing division, you can solve by doing multiplication. To start with, let's look at just the numerator:

    x3 + 3x2 + 3x + 1 = (x+1)(x2 + Mx + C)

    Multiply the right hand side to remove the brackets, and equate the coefficients on each side to determine the values of the unknowns M and C.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook