Factorizing 2ab - 4ac + bd - 2de | Help Appreciated

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Factorize the following

2ab - 4ac + bd - 2de

cant get this at all

any help is appreciated
 
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Dave06 said:
Factorize the following

2ab - 4ac + bd - 2de

cant get this at all

any help is appreciated
Immediately you can get 2a(b-2c)+d(b-2e).

If you have a typo (e should be c?), then you have (2a+d)(b-2c).
 
im afraid not

the question asks

Factorise the following expressions by extraction or grouping of the common factors

2ab - 4ac + bd - 2de
 
Then the best you can do is, as mathman said, 2a(b- 2c)+ d(b- 2e).
 

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