1. The problem statement, all variables and given/known data(adsbygoogle = window.adsbygoogle || []).push({});

N has total 105 factors including 1 and N. then find :

a) the total no of odd factors between 1 and N.

b) if the total number of divisors of N which are multiple of 36 are 45.then the total no of odd factors between 1 and N.

c)the number of ways in which N can be resolved into 2 factors which are relatively prime to each other is equal to 4,then the total no of odd factors between 1 and N.

d) if the total number of divisors of N which are multiple of 216 are 48,then the total no of odd factors between 1 and N.

3. The attempt at a solution

total number of divisors of a number a^n1*b^n2*c^n3 is equal to (n1+1)(n2+1)(n3+1)

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# Homework Help: Factors of a number

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