Failed rocket problem (momentum conservation, Kleppner 4-4)

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SUMMARY

The forum discussion centers on the analysis of a rocket problem from Kleppner's "An Introduction to Mechanics," specifically problem 4-4, which involves momentum conservation and trajectory analysis. Participants agree that the rocket's initial powered flight complicates the trajectory, making it impossible to assume a simple parabolic path without additional information about the rocket's horizontal velocity at the moment of explosion. The consensus is that for a consistent solution, one must assume the rocket burns out immediately after launch, transitioning to a parabolic free fall trajectory.

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Michael Korobov
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Homework Statement
An instrument-carrying rocket accidentally explodes at the top of its trajectory. The horizontal distance between the launch point and the point of explosion is L. The rocket breaks into two pieces that fly apart horizontally. The larger piece has three times the mass of the smaller piece. To the surprise of the scientist in charge, the smaller piece returns to Earth at the launching station. How far away does the larger piece land? Neglect air resistance and effects due to the Earth’s curvature.
Relevant Equations
Momentum conserved
Kinematics equations
Hi,
Can anyone hint me if there is issue in the problem statement?
Consistent answer can be obtained if one presumes that the trajectory of center mass is parabolic.
Assuming this, the CM will land at distance L right to the axis of symmetry of parabola.
But the problem tells about a rocket, therefore first part of rocket movement is not free fall and thus the horizontal distance of falling after the top of trajectory is not necessarily L.
Is it deduction correct?
 
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Michael Korobov said:
But the problem tells about a rocket, therefore first part of rocket movement is not free fall and thus the horizontal distance of falling after the top of trajectory is not necessarily L.
Is it deduction correct?
Yes, it is not necessarily L. That's why the scientist in charge was surprised when it landed there.
 
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Michael Korobov said:
But the problem tells about a rocket, therefore first part of rocket movement is not free fall and thus the horizontal distance of falling after the top of trajectory is not necessarily L.
Is it deduction correct?
If we assume powered flight all the way to the top of the trajectory then we have, in principle, no way to know the horizontal velocity of the rocket just prior to the explosion.

It is possible, for instance, that the rocket reverses course, that the "explosion" is a mere fizzle and that both rocket pieces land together at the launch site.

Accordingly, one assumes, as you did in your solution, that the rocket burns out almost immediately after launch and then carries on in a parabolic free fall trajectory. Otherwise, there is no way to a solution.
 
jbriggs444 said:
If we assume powered flight all the way to the top of the trajectory then we have, in principle, no way to know the horizontal velocity of the rocket just prior to the explosion.

It is possible, for instance, that the rocket reverses course, that the "explosion" is a mere fizzle and that both rocket pieces land together at the launch site.

Accordingly, one assumes, as you did in your solution, that the rocket burns out almost immediately after launch and then carries on in a parabolic free fall trajectory. Otherwise, there is no way to a solution.
Indeed, this was the only way to get consistent solution.
Thanks!
 

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