christopherV
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Does a photon actually travel faster than c during quantum tunneling? Where does the extra energy come from if a photon is massless? I am still unclear on this...
The discussion centers on the impossibility of objects with mass accelerating to the speed of light, denoted as "c". It is established that while massless entities, such as photons, travel at c, they do not accelerate to this speed; they are emitted at c. The conversation also touches on the concept that changes in electromagnetic fields can propagate faster than light, but no actual mass or massless particles can exceed this speed. Additionally, the effects of gravity on light are clarified, emphasizing that light does not accelerate but rather follows a curved path due to spacetime geometry.
PREREQUISITESPhysicists, students of physics, and anyone interested in the fundamental principles of light speed and relativity will benefit from this discussion.
Excuse me, but always I read it; it sounds like dogmas to me that cannot be proven or disproven."Nothing with mass can accelerate to the speed of light. The closer you get to it, the more energy it will take to get closer. It is an asymptotic limit."
"No. Anything with no mass travels AT the speed of light. E.g. light."
"Light does not accelerate. It is emitted at c."
"Regardless, the photon moves at c and only c. Photons do not experience time."
"As I mentioned earlier, the individual photons still travel at c."
"In medium, the actual photons still travel at the speed of light."
Your ignorance of the experimental results does not imply that the experimental results do not exist. See the sticky on the experimental basis of SR for a good concise overview. Many experiments involve high speed neutrinos and neutrons from various nuclear reactions, so your assertions about only using charged particles are incorrect. There are also experiments with large objects like satellites and planes which are also electrically neutral.Cosmos2001 said:it sounds like dogmas to me that cannot be proven or disproven.
Well, the minimum amount of energy required to accelerate a neutron close to speed of light:DaleSpam said:Your ignorance of the experimental results does not imply that the experimental results do not exist. See the sticky on the experimental basis of SR for a good concise overview. Many experiments involve high speed neutrinos and neutrons from various nuclear reactions, so your assertions about only using charged particles are incorrect. There are also experiments with large objects like satellites and planes which are also electrically neutral.
Is this your attempt to overturn the "dogma" that massive objects cannot reach or exceed c?Cosmos2001 said:Well, the minimum amount of energy required to accelerate a neutron close to speed of light:
neutron=1.67493×10-27 kg
c=299792458 m/s
E=½mv²
EJ=½(1.67493×10-27)(299792458)² =75.26760×10-12J
EeV=75.26760×10-12/1.60218×10-19 = 469.78242×106 = 470MeV
The average energy released in fission of one Pu-239 atom is 210MeV, emitted neutrons 5.9MeV which is very far from 470MeV, there is not enough energy to emit neutron close to speed of light.
http://en.wikipedia.org/wiki/Plutonium-239#Nuclear_properties
My question is: are there atomic nucleuses that emit neutrons having kinetic energy exceeding 470MeV?
First, you need to learn the right formulas. E=½mv² is the non-relativistic kinetic energy not the relativistic kinetic energy. 470 MeV of KE accelerates a neutron to about .75 c (gamma factor 1.5).Cosmos2001 said:Well, the minimum amount of energy required to accelerate a neutron close to speed of light:
neutron=1.67493×10-27 kg
c=299792458 m/s
E=½mv²
EJ=½(1.67493×10-27)(299792458)² =75.26760×10-12J
EeV=75.26760×10-12/1.60218×10-19 = 469.78242×106 = 470MeV
The average energy released in fission of one Pu-239 atom is 210MeV, emitted neutrons 5.9MeV which is very far from 470MeV, there is not enough energy to emit neutron close to speed of light.
http://en.wikipedia.org/wiki/Plutonium-239#Nuclear_properties
My question is: are there atomic nucleuses that emit neutrons having kinetic energy exceeding 470MeV?
DaleSpam said:First, you need to learn the right formulas.
“470 MeV of KE accelerates a neutron to about .75 c (gamma factor 1.5)”DaleSpam said:First, you need to learn the right formulas. E=½mv² is the non-relativistic kinetic energy not the relativistic kinetic energy. 470 MeV of KE accelerates a neutron to about .75 c (gamma factor 1.5).
Second, that amount of energy would result in approximately a 50% deviation from classical behavior. Well designed experiments can easily be made to detect deviations from classical behavior of less than 1% which would correspond to a KE of less than about 9 MeV.
Third, if you have a high KE particle which undergoes a nuclear reaction and releases a neutron then the KE of the neutron will be more determined by the high KE of the original particle than by the energy released from the nuclear reaction. This is how most high energy neutrons are actually produced in the lab.
Cosmos2001 said:“470 MeV of KE accelerates a neutron to about .75 c (gamma factor 1.5)”
Is it a fact? Or supposition by indirect means?
How to make sure, in fact, that a neutron having more than 470 MeV of KE will not exceed the speed of light?
It's just science! I only want to know the truth of it all.
Cosmos2001 said:Is it a fact? Or supposition by indirect means?
How to make sure, in fact, that a neutron having more than 470 MeV of KE will not exceed the speed of light?
It's just science! I only want to know the truth of it all.
High energy neutrons from cosmic rays have been detected with energies in the range of 10^12 MeV without exceeding the speed of light. What's more, relativistic effects have been measured in macroscopic neutrally-charged objects like airplanes and satellites. If you really want to know the truth of it all then look at the evidence:Cosmos2001 said:“470 MeV of KE accelerates a neutron to about .75 c (gamma factor 1.5)”
Is it a fact? Or supposition by indirect means?
How to make sure, in fact, that a neutron having more than 470 MeV of KE will not exceed the speed of light?
It's just science! I only want to know the truth of it all.
I know that, in particle accelerators, both negatively and positively charged particles need an outrageous energy (GeV, TeV, or much more) to attain to 99% of the speed of light. And particle accelerators are unable to accelerate neutrons. I think fast charged particles are easily slowed down by electric and magnetic fields, while fast neutrons are not so easily slowed down.DaleSpam said:High energy neutrons from cosmic rays have been detected with energies in the range of 10^12 MeV without exceeding the speed of light. What's more, relativistic effects have been measured in macroscopic neutrally-charged objects like airplanes and satellites. If you really want to know the truth of it all then look at the evidence:
http://www.edu-observatory.org/physics-faq/Relativity/SR/experiments.html
Cosmos2001 said:DaleSpam, please, I’m not finding out the info 10^12 MeV, could give me more direct links?
MattRob said:Haha, Merlin would tell you that's perfectly normal, Brown Arrow
Here is a classic with the full text. It only goes up to 10^6 MeV, but that is still far higher than your 470 MeV threshold that you are worried about.Cosmos2001 said:DaleSpam, please, I’m not finding out the info 10^12 MeV, could give me more direct links?
DaveC426913 said:Regardless, the photon moves at c and only c.
“No. Anything with no mass travels AT the speed of light. E.g. light.” – K^2
“Regardless, the photon moves at c and only c. Photons do not experience time.” – DaveC426913
“As I mentioned earlier, the individual photons still travel at c.” – Danger
“In medium, the actual photons still travel at the speed of light.” – K^2
“Nothing can locally travel faster than light” – Miguel Alcubierre
Sure, nothing is wrong with this. In this case v is the phase velocity of the wave, which is not limited to c and does not violate SR in any way as no matter, energy, or information is traveling faster than c.Cosmos2001 said:Hypothesis:
Having an array of dipoles, floating in the deep space, producing spaced-apart phase-shifted oscillations, generating strong/energetic “moving electrodynamic wave packet” along the array length, where the velocity of the “moving wave packet” is given by v=Lf (ref.: multiphase linear motors), where v is the velocity, L is the array length, and f is frequency.
If (f > c/L) then (v>c) and (∆v=v-c)
What is being accelerated here? The phase velocity is not the velocity of any object and so it doesn't need any time to accelerate.Cosmos2001 said:Keeping energy flow enough to keep acceleration (∆v/∆t):
In an initial case, v is more the velocity of the “moving electrodynamic wave packet” that is being generated by the array of dipoles that is adjustable v=Lf (ref.: multiphase linear motors)DaleSpam said:Sure, nothing is wrong with this. In this case v is the phase velocity of the wave, which is not limited to c and does not violate SR in any way as no matter, energy, or information is traveling faster than c.
What is being accelerated here? The phase velocity is not the velocity of any object and so it doesn't need any time to accelerate.
I thought the dipoles were just generating the wave with phase velocity v>c. If the dipoles are being accelerated then what is doing the accelerating? Your setup is not very clear.Cosmos2001 said:The array of dipoles is that which have mass and is to be accelerated. I was anticipating the overall energy requirement.
russ_watters said:Infinity is not a number - that's why it is undefined.
I’m sorry; it is difficult to me to express it in a clearer form.DaleSpam said:I thought the dipoles were just generating the wave with phase velocity v>c. If the dipoles are being accelerated then what is doing the accelerating? Your setup is not very clear.
In any case, dipoles work according to Maxwell's equations so you will never get a group velocity >c or any material object traveling with v>c.
No, only the phase velocity will be >c. Energy does not move at the phase velocity.Cosmos2001 said:The energy in each dipole will never travel faster than c, but the overall energy moving along the array length will be forced (v>c),
I don't know how you arrive at this conclusion. The array of dipoles won't move at all, dipole radiation is symmetric.Cosmos2001 said:however, in the surrounding medium the speed is limited to c. To prevent speed violation; the array of dipoles will be forced to move to the opposite direction, doing (v=c), evicting energy flow faster than c.
Not even remotely. Lots of experiments have been done with phase velocities >c. The kind of propulsion you envision doesn't exist. There is no "traction" from phase velocities like you are supposing. In fact, there is no physical significance to phase velocities >c at all any more than there is a physical significance to the velocity of the "dot" from a laser pointer.Cosmos2001 said:If an object is traveling at low speed, vacuum doesn’t offer both support and resistance to change velocity. If the object is traveling close to c, it will offer resistance. The idea here is to take advantage of the resistance transforming it into support for initial acceleration of massive objects. Is it possible?
In a multiphasic linear motor, if (v<c), energy move at the phase velocity, it is hard to refute this; I think is a true fact for (v<c) because without this the linear motor would not work.DaleSpam said:No, only the phase velocity will be >c. Energy does not move at the phase velocity.
I don't know how you arrive at this conclusion. The array of dipoles won't move at all, dipole radiation is symmetric.
Not even remotely. Lots of experiments have been done with phase velocities >c. The kind of propulsion you envision doesn't exist. There is no "traction" from phase velocities like you are supposing. In fact, there is no physical significance to phase velocities >c at all any more than there is a physical significance to the velocity of the "dot" from a laser pointer.