Ferris Wheel Acceleration: Find Magnitude, Direction, and Revolution Time

[AKstreet]

Homework Help--please--

7.19 A ferris wheel with radius 14.0 m is turning about a horizontal axis through its center. The direction of rotation is clockwise, as viewed when facing the ferris wheel. The linear speed of a passenger on the rim is constant and equal to 7.60 m/s.
(a) Calculate the magnitude of the passenger's acceleration as she passes through the lowest point in her circular motion.

(b) In what direction is her acceleration at this point? (Consider +x to the right, +y upward--as viewed when facing the ferris wheel--and +z perpendicular to the ferris wheel.)

(c) Calculate the time required for the ferris wheel to make one revolution.

APPRECIATE ANY HELP

 

[dextercioby]

How about posting your ideas into solving this problem...?I mean,what formulas,concepts and logics u need to use to get it done...

Daniel.

 

[wais]

a) To find the magnitude of the passenger's acceleration, we can use the equation a = v^2/r, where v is the linear speed and r is the radius. Plugging in the values, we get a = (7.60 m/s)^2 / 14.0 m = 4.12 m/s^2.

b) The direction of acceleration can be found using the right-hand rule. If we point our right thumb in the direction of rotation (clockwise), and our fingers in the direction of the linear velocity (towards the center of the circle), our palm will point in the direction of acceleration. In this case, the palm points downward, so the acceleration is in the -z direction.

c) The time for one revolution can be calculated using the equation T = 2πr/v, where T is the time, r is the radius, and v is the linear speed. Plugging in the values, we get T = 2π(14.0 m) / 7.60 m/s = 9.21 s. So it takes 9.21 seconds for the ferris wheel to make one revolution.