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Does Feynman's path integral formulation violate relativity ,
we get path's that are faster than c.
we get path's that are faster than c.
Feynman's path integral formulation does not violate the principles of relativity, as the paths generated are purely mathematical constructs and do not represent actual particle trajectories. The concern regarding paths that exceed the speed of light (c) is addressed by the fact that the probability amplitude for such occurrences remains zero. Thus, while the formulation allows for theoretical paths, they do not translate into physical realities that contradict relativistic constraints.
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