Fiber Optic Loop: How Long Before Photon Dissipation?

AI Thread Summary
In a closed loop of fiber optics, the dissipation of a photon’s energy is influenced by the glass's purity and the presence of defects. The less defective the fiber, the longer the photon can maintain its intensity. A typical multimode fiber experiences an attenuation of about 2 dB per kilometer, meaning a photon could travel approximately 17 kilometers before its intensity drops to 0.1% of its original value. The discussion highlights the importance of fiber quality in various applications, including long-distance light transmission and laser technology. Overall, the longevity of a photon in a fiber optic loop is significantly affected by the material's characteristics.
Danyon
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Imagine a closed loop of fiber optics, How long will a photon be able to stay inside the loop before dissipating all it's energy, or does it not dissipate?
 
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Absorption of light in glass is not zero, it depends on how many defects in the glass. The less defects in the fiber, the more light will keep its intensity. As for a single photon, the probability of absorption similarly depends on the purity of the glass. Fibers carry light across oceans, and some lasers are created with fibers, so defects can be sufficiently reduced for a fiber to have many impressive applications.
 
Danyon said:
Imagine a closed loop of fiber optics, How long will a photon be able to stay inside the loop before dissipating all it's energy, or does it not dissipate?

Greetings Danyon

a tiny fraction of a second before it is absorbed :smile:
 
Note that a single photon cannot give up part of its energy. It's all or nothing.
 
I believe a typical attenuation for a multimode fibre would be say 2dB per kilometre (factor of 1.5). So I think if you defined "dissipated" to be when the intensity is down to say 1/1000th (0.1%) of it's original value it would need to travel about 17km. You can work out how long it would take to travel 17km.

Oops I was in a rush. Might be slightly out in my numbers.
 
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