Final temperature of sliver ring in calorimeter

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SUMMARY

The final temperature of a silver ring placed in a calorimeter can be calculated using the principle of heat transfer. In this scenario, a 25.5 g silver ring with a specific heat capacity (Cp) of 234 J/kg·°C is heated to 84°C and then placed in 0.050 kg of water at 24°C. A total of 0.140 kJ of energy is lost to the surroundings during the process. The final temperature is determined by applying the formula Q = m c ΔT, accounting for energy lost to the surroundings.

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  • Understanding of specific heat capacity and its units (J/kg·°C)
  • Familiarity with the concept of calorimetry
  • Knowledge of heat transfer principles
  • Ability to manipulate and solve equations involving mass, specific heat, and temperature change
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LezardValeth
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A 25.5 g silver ring (Cp = 234 J/kg times degrees C) is heating to a temperature of 84 degrees C and then placed in a calorimeter containing
5 x 10 to the negative 2 power kg of water at 24 degrees C. the calorimeter is not perfectly insulated, however, a 0.140 kJ of energy is transferred to the surroundings before a final temperature is reached. What is the final temperature?
 
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try this Q = m c \Delta T and think about which is transferring the energy and which is receiving the energy...then consider the amount of energy lost to the surroundings and how that would affect the final temp.
 
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