Find a parametrization of the vertical line passing through the point

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Homework Help Overview

The problem involves finding a parametrization of a vertical line that passes through the point (7, -4, 2), specifically using z = t as a parameter. The context is within the subject area of vector parametrization in three-dimensional space.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the use of the point (7, -4, 2) as a reference for the parametrization and the implications of using different forms of the equations. Questions arise regarding the redundancy of certain terms in the parametrization.

Discussion Status

The discussion includes various interpretations of the parametrization, with some participants suggesting that different forms can represent the same line. There is acknowledgment of the validity of multiple approaches without a clear consensus on a single preferred method.

Contextual Notes

Participants note that the choice of parameters can lead to different representations of the same line, raising questions about the conciseness and clarity of mathematical expressions in parametrization.

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Homework Statement


Find a parametrization of the vertical line passing through the point (7,-4,2) and use z=t as a parameter.


Homework Equations


r(t) = (a,b,c) + t<x,y,z>


The Attempt at a Solution


I used (7,-4,2) as (a,b,c) (the point) and used <0,0,1> for the vector since it had to be vertical and got the components to be
x=7
y=-4
z=2+t
 
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You might as well set z = t, it amounts to the same thing.
 
Ok, that's the right answer. Thank you
Why would what I did not be right?
 
What you did is not wrong; but the additive constant is redundant. Any mathematical expression can be written in a variety of ways with redundant terms, but such things are normally not done (unless used in some clever transformation). So you should always try to find the most concise form possible.
 
x= 7, y= 4,z= 2+ t has t=0 at (7, 4, 2) while x= 7,y= 4, z= t has t= 0 at (7, 4, 0), but they give the same line. Notice that, in the first set of equations, t= -2 gives (7, 4, 0) while, in the second set, t= 2 gives (7, 4, 2). Since a line is determined by two points, the lines defined by those sets of equations are the same line.

In fact, as long as f(x) is a one-to-one function that maps the real numbers onto the real numbers,
x= 7, y= 4, z= f(t) are parametric equations for that line.
 

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