Find a particular solution that satisfies the intial condition

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SUMMARY

The discussion focuses on solving the separable differential equation given by 2xy' - ln(x²) = 0 with the initial condition y(1) = 2. The equation is simplified using the property ln(x²) = 2ln(x), leading to the form 2x(dy/dx) = 2ln(x). The next steps involve separating variables and integrating both sides, followed by applying the initial condition to find the constant of integration.

PREREQUISITES
  • Understanding of differential equations, specifically separable equations.
  • Familiarity with logarithmic properties, particularly ln(x²) = 2ln(x).
  • Basic integration techniques and the concept of the constant of integration.
  • Knowledge of initial value problems and how to apply initial conditions.
NEXT STEPS
  • Practice solving separable differential equations using various initial conditions.
  • Review integration techniques, focusing on integrating logarithmic functions.
  • Explore the concept of initial value problems in differential equations.
  • Learn about the implications of the constant of integration in different contexts.
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Students studying differential equations, mathematics educators, and anyone seeking to enhance their problem-solving skills in calculus and mathematical analysis.

Ki-nana18
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Homework Statement


2xy'-ln x2=0 y(1)=2


Homework Equations





The Attempt at a Solution


2x(dy/dx)-ln x2=0

I think I'm suppose to separate variables and then integrate next but I'm not sure.
 
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Yes, this is a separable differential equation.

You should use the fact that ln(x2) = 2ln(x).

2x*dy/dx = 2 ln(x)
[tex]\Rightarrow~dy~=~ \frac{ln(x)}{x}dx[/tex]

Now integrate both sides. Don't forget the constant of integration, which you will determine from your initial condition, y(1) = 2.
 

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