Ki-nana18 Messages 90 Reaction score 0 Thread starter Nov 24, 2009 #1 Homework Statement 2xy'-ln x2=0 y(1)=2 Homework Equations The Attempt at a Solution 2x(dy/dx)-ln x2=0 I think I'm suppose to separate variables and then integrate next but I'm not sure.
Homework Statement 2xy'-ln x2=0 y(1)=2 Homework Equations The Attempt at a Solution 2x(dy/dx)-ln x2=0 I think I'm suppose to separate variables and then integrate next but I'm not sure.
Mark44 Mentor Insights Author Messages 38,138 Reaction score 10,725 Nov 24, 2009 #2 Yes, this is a separable differential equation. You should use the fact that ln(x2) = 2ln(x). 2x*dy/dx = 2 ln(x) [tex]\Rightarrow~dy~=~ \frac{ln(x)}{x}dx[/tex] Now integrate both sides. Don't forget the constant of integration, which you will determine from your initial condition, y(1) = 2.
Yes, this is a separable differential equation. You should use the fact that ln(x2) = 2ln(x). 2x*dy/dx = 2 ln(x) [tex]\Rightarrow~dy~=~ \frac{ln(x)}{x}dx[/tex] Now integrate both sides. Don't forget the constant of integration, which you will determine from your initial condition, y(1) = 2.