Find a Point for x=5: Help Appreciated | Direction Vector = (0,1)

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To find a point on the line defined by x=5, the second coordinate can be any real number, leading to points of the form (5, a). The equation x + 0y - 5 = 0 confirms that x must equal 5, while y remains unrestricted. Examples of valid points include (5, 0) and (5, 6). The discussion emphasizes that multiple points can satisfy the condition, as long as the x-coordinate is fixed at 5. The key takeaway is that any point (5, a) where 'a' is any real number is acceptable.
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for each of the following, find a point on each line:

x=5

:D LOl ok this is what i thought

x+0y-5=0

so direction vector=(0,1)

If I set x to 5 then y should = 0 shouldn't it?
 
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thomasrules said:
for each of the following, find a point on each line:

x=5

:D LOl ok this is what i thought

x+0y-5=0

so direction vector=(0,1)

If I set x to 5 then y should = 0 shouldn't it?

First think about what would happen if you didn't set x equal to 5, say you set x equal to 6 what happens?

You don't set x equal to 5, x is 5 period end of story, that is what you're given all points on that line are of the form (5,a) where a is any real number. You just need one point, I think you can figure it out from here.
 
yea I just saw at the back of the book it said (5,6) and I had no idea where that came from
 
READ the problem! It said "find a point on each line". How many points are there on a line? Since the equation is x= 5, obviously the first coordinate must be 5. What about the second coordinate? What does that equation tell you about y? How does that equation restrict y?

Your answer, (5, 0), is a perfectly good answer. So is (5, 6). So is
(5, 323121232344).
 
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