Find and Sketch the Domain of a Function

AI Thread Summary
The function ƒ(x,y) = √y + √[25-x²-y²] is defined for the conditions y ≥ 0 and x² + y² ≤ 25. The region satisfying x² + y² ≤ 25 represents a circle with a radius of 5 centered at the origin. The condition y ≥ 0 restricts this region to the upper half of the circle. The intersection of these two regions forms a semicircle in the upper half-plane. Understanding these shapes is crucial for graphically representing the domain of the function.
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Homework Statement


ƒ(x,y) = √y + √[25-x2-y2]

Homework Equations


Quadratic

The Attempt at a Solution


The expression for f(x,y) is defined as long as x2 + y2 ≥ 25 and y ≥ 0 because of the square roots we can't have negative numbers. {(x,y) ∈ ℝ2 : y ≥ 0 and x2 + y2 ≥ 25} I'm not sure how I'd represent it graphically.
 
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What is the shape of the region of the number plane that satisfies ##x^2+y^2\leq 25##?
What is the shape of the region of the number plane that satisfies ##y\geq 0##?
What is the shape of the intersection of those two regions?
 
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...
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