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Find angle between vectors with cosine law

  1. Sep 12, 2007 #1
    Hi

    I would really appreciate it if anybody could lead me in the right direction on this one...

    |A| = |B|

    |A+B| = 100|A-B|

    I need to find the angle between A and -B for the statement to be true.

    Using cosine laws I've come up with the following eqn:

    |A+B| = 100|A-B|
    2|A|^2 + (2|A|^2)(cosx) = 100[2|A|^2 - (2|A|^2)(cosx)]

    I applied these cosine laws to the isosceles triangles

    I'm not looking for the answer, I'm just looking to get some guidelines on solving for x, the angle.

    Thanks so much

    note: A and B are vectors.
     
    Last edited: Sep 12, 2007
  2. jcsd
  3. Sep 12, 2007 #2

    D H

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    Staff Emeritus
    Science Advisor

    Simply divide by |A|^2 (even though A is a vector, its magnitude is a scalar) and solve for cosx.
     
  4. Sep 12, 2007 #3
    Ah yes, I should've know. I always over complicate myself! Thanks for the help!
     
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