Find Arc Length of Particle Moving on Curve

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To find the arc length of a particle moving along the curve defined by r(t) = a(cos t + t sin t)i + a(sin t - t cos t)j over the interval 0 to 2pi, the correct formula involves integrating the magnitude of the derivative r'(t). The derivative was incorrectly calculated, leading to an integration that resulted in zero. The proper approach requires maintaining the vector components and using the correct arc length formula, which is the integral of the magnitude of r'(t). The expected result for the arc length is 2pi^2a. Correcting the derivative and integration process is essential to obtaining the accurate arc length.
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Homework Statement



Find the length of the path traced out by a particle moving on a curve according to the given equation during the time interval specified in each case.

The equation is r(t) = a(cos t + t sin t)i + a(sin t - t Cos t)j, 0</=t</=2pi, a>0

Homework Equations



Arc length = interval (r'(t)dt)

The Attempt at a Solution



I found the derviative of r(t) to be r'(t) = cost + tsint +atcost +sintt -tcost +atsint
Integrating this from 0->2pi I keep getting 0 because it is subtracting itself. The answer is supposed to be 2pi2a. What am I doing wrong?[/B]
 
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##\vec{r}(t)## is a vector as is its derivative. You can't simply erase the ##\hat{i}## and ##\hat{j}##.
 
And the formula for arc length (integral, not interval) is incorrect. The integrand is ##|\vec r'(t)|##.
 
Question: A clock's minute hand has length 4 and its hour hand has length 3. What is the distance between the tips at the moment when it is increasing most rapidly?(Putnam Exam Question) Answer: Making assumption that both the hands moves at constant angular velocities, the answer is ## \sqrt{7} .## But don't you think this assumption is somewhat doubtful and wrong?

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