Find the arc length parametrization of a curve

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SUMMARY

The discussion focuses on finding the arc length parametrization of the curve defined by the vector function r(t) = (3t cos(t), 3t sin(t), 2√2 t^(3/2)). The key equation used is s(t) = ∫|r'(t)| dt, which simplifies to s(t) = ∫√(9(1+t)²) dt, resulting in s(t) = 3t + (3/2)t². The challenge arises in solving for t in terms of s, which is identified as a quadratic equation, indicating a straightforward resolution method that was overlooked.

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  • Familiarity with solving quadratic equations
  • Proficiency in integral calculus
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AramN
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Homework Statement


Find the arc length parametrization of the curve r = (3t cost, 3tsint, 2sqrt(2)t^(3/2) ) .

Homework Equations


s(t)=integral of |r'(t)| dt

The Attempt at a Solution


I was able to get the integral of the magnitude of the velocity vector to simplify to:
s(t) = integral of sqrt(9(1+t)^2) dt
evaluating the integral, s(t) = 3t+(3/2)t^2
In other problems similar to this one I would solve for t in terms of s then put it back into the original equation, but for this one I was unable to solve for t in terms of s.
 
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AramN said:

Homework Statement


Find the arc length parametrization of the curve r = (3t cost, 3tsint, 2sqrt(2)t^(3/2) ) .

Homework Equations


s(t)=integral of |r'(t)| dt

The Attempt at a Solution


I was able to get the integral of the magnitude of the velocity vector to simplify to:
s(t) = integral of sqrt(9(1+t)^2) dt
evaluating the integral, s(t) = 3t+(3/2)t^2
In other problems similar to this one I would solve for t in terms of s then put it back into the original equation, but for this one I was unable to solve for t in terms of s.

I don't see the problem in solving for t. It's just a quadratic equation.
 

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