Find area of surface obtained by rotating the curve, ?

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SUMMARY

The discussion focuses on calculating the area of the surface obtained by rotating the curve defined by the equation y = x + √x, over the interval [1, 2], about the x-axis using Simpson's rule with n=10. The integral setup is correctly expressed as S = 2π ∫ (x + √x)√[2 + 1/√x + 1/(4x)] dx from x=1 to 2. Despite the correct setup, the initial poster's calculations yielded an approximate area of 27.68876, which they believe to be incorrect. Participants suggest verifying calculations and comparing results with tools like WolframAlpha for accuracy.

PREREQUISITES
  • Understanding of calculus concepts, specifically surface area of revolution
  • Familiarity with Simpson's rule for numerical integration
  • Knowledge of integral calculus and function evaluation
  • Experience with mathematical software or tools for verification, such as WolframAlpha
NEXT STEPS
  • Review the application of Simpson's rule in numerical integration
  • Learn how to set up integrals for calculating surface areas of revolution
  • Explore the use of WolframAlpha for verifying complex mathematical calculations
  • Study the properties of the function g(x) = (x + √x)√[2 + 1/√x + 1/(4x)] for better understanding
USEFUL FOR

Students and professionals in mathematics, particularly those focused on calculus, numerical methods, and surface area calculations. This discussion is beneficial for anyone seeking to enhance their skills in applying Simpson's rule and verifying complex integrals.

ani9890
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Find area of surface obtained by rotating the curve, URGENT?

Using Simpson's rule n=10, find the area of the surface obtained by rotating the curve
y=x+sqrt(x), 1 less than or equal to x less than or equal to 2, about the x-axis.
Include at least five decimal places in your answer.
Area = ?

I got:

S = = 2π ∫ (x + √x)√[2 + 1/√x + 1/(4x)] dx (from x=1 to 2).
∆x = (2 - 1)/10 = 1/10.
S ≈ (2π)(1/3)(1/10){g(1) + 4g[1 + 1(1/10)] + 2g[1 + 2(1/10)] + 4g[1 + 3(1/10)] + 2g[1 + 4(1/10)] + 4g[1 + 5(1/10)] + 2g[1 + 6(1/10)] + 4g[1 + 7(1/10)] + 2g[1 + 8(1/10)] + 4g[1 + 9(1/10)] + g(2)}
≈ (π/15)[(1 + 1)√(2 + 1 + 1/4) + 4(20.653233395588) + 2(20.119929259013) + (2 + √2)√(2 + 1/√2 + 1/8)]
≈ 27.68876.

But this is wrong. Please help!
 
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ani9890 said:
Using Simpson's rule n=10, find the area of the surface obtained by rotating the curve
y=x+sqrt(x), 1 less than or equal to x less than or equal to 2, about the x-axis.
Include at least five decimal places in your answer.
Area = ?

I got:

S = = 2π ∫ (x + √x)√[2 + 1/√x + 1/(4x)] dx (from x=1 to 2).
∆x = (2 - 1)/10 = 1/10.
S ≈ (2π)(1/3)(1/10){g(1) + 4g[1 + 1(1/10)] + 2g[1 + 2(1/10)] + 4g[1 + 3(1/10)] + 2g[1 + 4(1/10)] + 4g[1 + 5(1/10)] + 2g[1 + 6(1/10)] + 4g[1 + 7(1/10)] + 2g[1 + 8(1/10)] + 4g[1 + 9(1/10)] + g(2)}
Why do you have the factor of 1/3 at the beginning of your calculation?
I don't think that should be there.

In your calculations for g(1), g(1.1), etc. does g(x) = (x + √x)√[2 + 1/√x + 1/(4x)]? You didn't say what g was, so I thought I would check.

I don't see anything wrong - your integral is set up correctly and your Simpson's work looks fine, so it would be worthwhile to doublecheck your calculations. The function you're evaluating is pretty complicated, and it would be easy to get incorrect values.

How are you determining that your answer is incorrect? Are you given the answer or is some computer program saying your answer is wrong? I would compare my results to those obtained from wolframalpha and see how close I got.
ani9890 said:
≈ (π/15)[(1 + 1)√(2 + 1 + 1/4) + 4(20.653233395588) + 2(20.119929259013) + (2 + √2)√(2 + 1/√2 + 1/8)]
≈ 27.68876.

But this is wrong. Please help!
 

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