Find average acceleration from two given velocities each at a given ti

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SUMMARY

The discussion focuses on calculating the average acceleration of an object transitioning from a velocity of 40 m/s due North at t=0 seconds to 30 m/s due East at t=5 seconds. The correct method involves vector addition rather than the Pythagorean Theorem, which yielded an incorrect result of 50 m/s at 36.9 degrees East of North. To find the average acceleration, one must determine the change in velocity components in both the North-South and East-West directions and then divide by the time interval of 5 seconds.

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The velocity of an object at t=0 seconds is 40 m/s directed due North. The velocity of the same object at t=5 seconds is 30 m/s directed due east.

Find the magnitude of the average acceleration of the object over the time interval from t=0 to t=5 seconds.

Also, show the direction of the average acceleration. So... I am not quite sure how to even approach this problem. I originally tried it and did it with Pythagorean Theorem, but my answer was incorrect.

The answer I got using Pythagorean Theorem was 50 m/s at 36.9 East of North.

Please help!
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Judging from your diagrams, you did a vector addition of the two velocities. You want the change involved in going from one velocity to the other. What operation should you use?
 
First consider the component of acceleration in the north-south direction. What is the change in the velocity component in this direction? From this, what is the acceleration (don't forget to divide by the time)?

Now do the same thing for the east-west direction.
 

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