- #1

Punkyc7

- 420

- 0

y=sqrt(4Ax)

K is what I am saying is proportional to x

xbar=My/m

ybar=MX/m

Im not concerned with the answers of xbar and ybar, just the concept of setting up the integrals.

For M we integrate ksqrt(4Ax) dx from -A to A

for My we intgrate k(xtilda)*(ksqrt(4Ax)) dx from -A to A, xtilda=x

for Mx we integrate k(ytilda)*(ksqrt(4Ax) dx from -A to A, ytilda= (ksqrt(4Ax)-ksqrt(4Ax))/2

I just want to make sure I am doing this right. Also I am not sure if the second k term should be included in My and Mx