Find Critical Numbers: Easier Way to Solve

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Discussion Overview

The discussion focuses on the process of finding critical numbers in calculus, exploring methods and clarifying definitions related to critical points and points of inflection. It includes theoretical explanations and examples.

Discussion Character

  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • Some participants inquire about easier methods for finding critical numbers beyond plugging in values until reaching zero.
  • One participant mentions a theorem related to finding critical numbers but does not specify which theorem.
  • Another participant explains the standard method of taking the derivative of a function, setting it to zero, and solving for critical numbers, providing an example with the function y=x^2+x.
  • A question is raised about whether points of inflection are also considered critical points.
  • Another participant clarifies that critical points occur where the derivative is zero or undefined, while points of inflection are related to the second derivative changing sign.
  • An example is given involving the function f(x)=x^3-3x to illustrate the distinction between critical points and inflection points.

Areas of Agreement / Disagreement

Participants generally agree on the method for finding critical numbers, but there is disagreement regarding the relationship between critical points and points of inflection.

Contextual Notes

Some assumptions about the definitions of critical points and points of inflection are present, but these are not universally accepted, leading to differing interpretations.

afcwestwarrior
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how do you find critical numbers, and do you have to keep on plugging in a number until you find zero or is their an easier way
 
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i know the theorem already
 
What theorem are you referring to?

You take the derivative of the function, set it equal to zero, and solve.
 
usually we take derivative of function and set it equal to 0 like hage567 said
for example you consider this function
y=x.x+x=x(2)+x
y'=dy/dx
y'=2x+1
for finding the critical number we set it to zero
y'=0
=> 2x+1=0
=> 2x=-1
=> x=-1/2
-1/2 is critical number for this function
and one of its usage is for finding the MAX. and MIN. of a function.
 
Aren't points of inflection also critical points?
 
No. Critical points are where either the derivative is 0 or where the derivative does not exist. Points of inflection are where the secondderivative changes sign. That has to be where the second derivative is 0 or does not exist although not all such points are inflection points.

For example, if f(x)= x3- 3x, then df/dx= 3x2- 3 so the critical points are x= 1 while d2f/dx2= 6x. The only inflection point is at x= 0.
 

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